Math Test

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Math Test

Postby admin » Tue Feb 22, 2011 3:01 pm

$\displaystyle{1+2+3+\cdots +n = \frac{n(n+1)}{2} }$
$\displaystyle{1^2+2^2+3^2+\cdots + n^2 = \frac{n(n+1)(2n+1)}{6} }$
$\displaystyle{1^3+2^3+3^3+\cdots + n^3 = \left(\frac{n(n+1)}{2} \right )^2 }$
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